2 November 2017

Parallel Operation of the Single Phase Transformer

  • When the primaries of two or more transformers are connected to common supply bus bars and secondary are connected to common load bus bars, the transformers are said to connect in parallel.

The parallel operation of transformers becomes necessary in following conditions. 

  • When the load power is greater than the power handled by single transformer. 
  • When expansion of the plant or additional load necessary, it is better to connect second transformer of suitable rating is in parallel with first transformer rather than using single transformer of higher capacity in the future. However the cost of single transformer of same rating is less than the cost of two transformers which are connected in parallel. 
  • Although the parallel operation is expansive but single transformer supply load when other transformer is in fault condition or take out of maintenance. 
  • The cost of stand by unit is reduced.
The following conditions should fulfilled when two or more transformers are connected in parallel.
Essential Conditions for Parallel Operation
( 1 ) The polarity of both transformers must be same
  • If the transformers are not connected in correct polarity, dead short circuit occurs. Let us know how to connect two transformers with correct polarity.
  • The primaries of both transformer are connected in parallel.
  • Connect the secondaries of transformers as shown in Figure A.
  • The rating of voltmeter must be double that of secondary rated voltage of the transformer.
  • If the voltmeter indicates zero, it is "correct'' polarity.
  • If the voltmeter indicates double voltage that of secondary rated voltage of a transformer, it is "incorrect'' polarity. In that case any one connection of the secondary winding is interchanged.

polarity-test-of-the-transformer.png

( 2 ) The turns - ratio of both transformers are the same

  • If the voltage ratio of the both transformer is not identical the secondary emf will induce resulting circulating current flow in the secondary circuit. 
  • Therefore the primaries of the transformer will draw reflected secondary circulating current, in addition to the magnetizing current. 
  • This additional current cause copper losses on both winding of the transformers.

( 3 ) Percentage impedance of the transformers is the same or X / R ratio should be the same for each transformer
  • If the percentage impedances of the transformers are not the same, a transformer with smaller percentage impedance will carry more load than its actual share load and other transformer carry only part of load. 
  • The impedance of the transformer is inversely proportional to its kVA rating.
  • If the X/R ratios of the transformers are different, one transformer will be operating with a higher power factor and the other transformer with a lower power factor that of total load. 
  • It means that kW load is not proportionally shared by them.

Vector diagram


vector-diagram-for-parallel-operation-of-single-phase-transformer.png

Let
V2 = Common terminal voltage
ZA = Impedance of transformer A
ZB = Impedance of transformer B
ZAB = Combined impedance of both transformers
E2 = Induced emf
IA = Load current shared by transformer A
IB = Load current shared by transformer B
  • Let us consider that both transformers have equal voltage ratio. 
  • From the vector diagram, it is seen that both transformers operate at lagging power of load.
  • Total impedance ZAB = ZA ½½ ZB

           ZAB = ( ZA ZB ) / ( ZA + ZB )
  • From Figure B

       IAZA = IBZB = IZAB
Therefore IA = ( ZA ZB ) / ( ZA + ZB ) [( I / ZA )]
          IA = I ZB  / ( ZA + ZB ). ………….( 1 )
Similarly 
           IB = ( ZA ZB ) / ( ZA + ZB ) [( I / ZB )]
           IB = IZ/ ( ZA + ZB )…………….( 2 )
Multiplying both side with V2 in the equation ( 1 ) and ( 2 )
      V2IA = V2I [ ZB  / ( ZA + ZB ) ]
        QA = Q [ ZB  / ( ZA + ZB ) ]
And
     V2IB = V2I [ Z/ ( ZA + ZB ) ]
       QB = Q [ ZA  / ( ZA + ZB ) ]
Where Q = Load kVA
        QA = kVA load share by transformer A
        QB = kVA load share by transformer B

You may also like :

Transformer as a Constant Flux device

Energy Balance Theory

Practical DC Generator

Armature Reaction in the DC Generator

No comments:

Post a Comment