Featured post

Estimation of Energy Storage Requirement by 2032

Energy storage requirement for Solar PV connected to grid In this post, energy storage requirement in India by 2032 is given here. The ESS r...

27/11/2020

Field Test

Introduction

  • The brake test is applicable only for small DC series motor. 
  • The field test is carried out on large DC series motor in order to find out various losses and efficiency.
  • There are two similar DC series motor requires in this test. 
  • The field winding of both series motors are connected in series in order to make iron losses of both machines are equal. 
  • One machine acts as a motor which drive a second machine as a separately excited generator. 
  • The output of the generator is connected to variable resistance load RL.

field-test-on-dc-series-motor


  • The motor M is started with help of starter. The voltage V1 across the motor terminals is kept equal to rated value. 
  • Obviously, the supply voltage V is equal to V1 plus voltage drop across the field winding of the generator. 
  • The load resistance RL is varies until the ammeter I1 show the full load current of the motor. 
  • Now the readings of the all meters are to be noted. 
  • The value of armature resistance is measured by V – I method or by using multi meter.

Let

V = Supply voltage

I1 = Motor input current

V1 = Voltage across motor

V2 = Output voltage of generator

I2 = Load current of generator

Ra = Hot armature resistance

Rse = Hot series field resistance

Now

Input of both machines = VI1

Output of both machines = VI2

Total losses of both machines ( Wt ) = VI1 – VI2

Armature copper losses of both machines = ( I1 + I2 )2 × Ra

Field losses of both machines = 2I12 × Rse

Stray losses per machine ( Ws )

= Wt – [ (( I1 + I2 )2 × Ra ) + 2I12 × Rse ] / 2

Motor efficiency

Motor input = V1I1

Motor losses = ( I1 + I2 )2 × Ra + Ws

Motor output = Motor input – Motor losses

= V1I1 – { ( I1 + I2 )2 × Ra + Ws }

Motor efficiency

= { Output power / Input power } × 100%

=  [ V1I1 – { ( I1 + I2 )2 × Ra + Ws } / V1I1 ] × 100%

Generator efficiency

Generator output = V2I2

Generator losses = I12 Rse + I22 Ra + Ws

Generator efficiency

= { Output power / Input power } × 100%

= { Output power / Output power + Losses } × 100%

= { V2I2 / ( V2I2 + I12 Rse + I22 Ra + Ws ) } × 100%

  • This is not regenerative test because the generator output is wasted instead of feedback to input of the motor.

You may also like :

Standard Alternating voltage in India

Compare Aluminum and Copper

Right of way ( ROW ) in the transmission line

Minimum Clearance between transmission line and Ground 


No comments:

Post a Comment